令t=1/x,则x=1/tx→0,t→∞lim[(2+x)/(2-x)]^(k/x)x→0=lim[(2+ 1/t)/(2- 1/t)]^(kt)t→∞=lim[(2t+ 1)/(2t- 1)]^(kt)t→∞=lim[(2t-1+2)/(2t- 1)]^(kt)t→∞=lim[1+ 1/(t- ½)]^[k(t-½)+½k]t→∞=lim[1+ 1/(t- ½)]^[k(t-½)]·[1+ 1/(t- ½)]^(½k)t→∞=e^k·1=e^k=e²k=2