用定积分求x=a(t-sint),y=a(1-cost)(0≤t≤pi)y=0,所围成图形的面积?

2025-12-17 10:29:37
推荐回答(1个)
回答1:

Area = ∫[0,pi] a^2(1-cost)^2 dt
= ∫[0,pi] a^2(1-2cost+cos^2t) dt
= ∫[0,pi] a^2[1-2cost+(1/2)(1+cos2t)] dt
= (3/2)pi a^2