A.n(H 2 SO 4 )=0.02L×0.1mol?L -1 =0.002mol,n(H + )=0.004mol,n(OH - )=0.03L×0.15mol?L -1 =0.0045mol,反应后碱过量,反应后的c(OH - )=
B.pH=3的HCl溶液和pH=11的氨水等体积混合液,氨水为弱电解质的溶液,氨水过量,反应后c(OH - )<0.001mol/L, ②中c(H + )=0.001mol/L,③中c(OH - )=0.001mol/L,c(H + )或c(OH - )越大,水的电离程度越小,则由水电离出的c(H + ):①>③=②,故B错误; C.常温下,0.1 mol/L HA(某酸)溶液pH≠l,说明HA为弱酸,但BOH的碱性强弱不确定,所以反应后溶液的酸碱性不确定,故C错误; D.已知酸性:CH 3 COOH>H 2 CO 3 >C 6 H 5 OH,酸性越弱,对应的盐水解程度越大,则pH相等时,浓度①>③>②,故D正确. 故选D. |