高中数学,第二题,求解题详细步骤

2025-05-09 14:17:50
推荐回答(1个)
回答1:

结果为3/2

原式=1/2[(cos2α)+1]+1/2{[cos(2α+120°)]+1}+1/2{[cos(2α+240°)]+1}
=1/2(cos2α)+1/2[cos(2α+120°)]+1/2[(cos2α+240°)]+3/2
=1/2(cos2α)+和差化积+3/2
=3/2