高一数学三角函数函数化简

2025-05-08 17:08:58
推荐回答(2个)
回答1:

如图

回答2:

原式=√cos2440+√(sin280+cos280-2sin80cos80) =|cos(360+80)|+√(sin80-cos80)2 =|cos80|+|sin80-cos80| =cos80+sin80-cos80 =sin80