求代数式3x2y?[2xy2?2(xy?32x2y)+xy]+3xy2的值,其中x=3,y=?13

求代数式3x2y?[2xy2?2(xy?32x2y)+xy]+3xy2的值,其中x=3,y=?13.
2025-05-11 05:35:05
推荐回答(1个)
回答1:

3x2y?[2xy2?2(xy?

3
2
x2y)+xy]+3xy2
=3x2y-2xy2+2xy-3x2y-xy+3xy2
=xy2+xy,
当x=3,y=?
1
3
时,原式=3×
1
9
-1=?
2
3