这个题怎么做,极限题,麻烦写一下步骤,谢谢?

第六题
2025-05-08 01:43:28
推荐回答(3个)
回答1:

看图片

回答2:

lim(x->π/3) (1-2cosx)/sin(x-π/3)
=lim(x->π/3) (1-2cosx)/(x-π/3)
=lim(x->π/3) (1-2cosx)/(x-π/3) (0/0 分子分母分别求导)
=lim(x->π/3) 2sinx
=2sin(π/3)
=√3

回答3:

利用诺必达法则,分子分母同时求导再取极限,步骤见下图